Posting out to 3rd party API

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Example of taking data in the form of a Model from your site and sending it out somewhere else and getting back a httpresponsemessage.
[HttpPost]
  public HttpResponseMessage Post(Appt_Model_DTO  appt)
        {

 >>>>You could eliminate this portion
  if (ModelState.IsValid)
            {
//not necessary but you can run some checks to make sure the data is good
//that the model is valid and there is not 
//you posted this data from your MVC site to your API Controller
//Now we are going to send it off to a third party site

                 if (appt.ID == null) {
                    appt.ID = my_provider.getRecordwithSameIdentity(appt.AccountCode);
                }
                appt.StartDateTime = DateTime.Now;
                if (appt.POSID ==0)
                {
                    return Request.CreateErrorResponse(HttpStatusCode.BadRequest, ModelState);

                 }
  >>>>>> And start here         
                        ZData z = new ZData();
                        z.AccountCode = appt.AccountCode;
                        z.AbbrevConceptName = appt.ConceptCode;
                        z.Comments = appt.Cust_Comments;
//Below line will need this reference declared  using Newtonsoft.Json;
                       string data = JsonConvert.SerializeObject(z);
   // Prepare web request...
//Declare the URL you will be posting to
  string myurl = "https://apiaddress.com/api/WebCall?v=1.00&key=31f9f4ff-811e-";

 HttpWebRequest myRequest = (HttpWebRequest)WebRequest.Create(myurl);
  
    try { 
    myRequest.Method = "POST";
            myRequest.KeepAlive = true;
            myRequest.ContentType= "application/json";
            myRequest.ContentLength = data.Length;
            var streamWriter = new StreamWriter(myRequest.GetRequestStream());
            streamWriter.Write(data);
            streamWriter.Close();
//Declare Response Object
  HttpWebResponse webresponse;
    webresponse = (HttpWebResponse)myRequest.GetResponse();
 //you could record response in a table
    return new HttpResponseMessage(webresponse.StatusCode);
    }
    catch (Exception e)
    {
        //write exception somewhere or send error email and return a failed response
      
        SendErrorEmail s = new SendErrorEmail();
        s.Send_Error(e);
        return new HttpResponseMessage(HttpStatusCode.ExpectationFailed);
    }

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